問題描述

問題解答

分兩種情況選出符合要求的company_id并union

把這些company_id的earning求和（2013-2014）

連接上company_name

好像搞的比較復雜。

with cid(id) as ( select company_id from tableB where year = 2014 and earning > 20 union select company_id from tableB where year in (2013, 2014) group by company_id having sum(earning) > 50), cid_earning(id, earning) as ( select company_id, sum(earning) from tableB where company_id in (select id from cid) and year in (2013, 2014) group by company_id)select a.company_name, c.earningfrom cid_earning c left join tableA a using(id)思路二

如果把2013和2014年的earning作為表的兩個field，SQL的邏輯會清晰很多：

withe3(id, earning) as ( select company_id, earning from tableB where year = 2013), e4(id, earning) as ( select company_id, earning from tableB where year = 2014)select a.company_name, e3.earning + e4.earning as earningfrom e3 inner join e4 using(id)left join tableA a using(id)where e4.earning > 20 or e3.earning + e4.earning > 50回答2：

好復雜哦，同問，這樣的sql怎么寫，我在想是不是可以寫個存儲過程，畢竟存儲過程處理這樣復雜的邏輯容易一點