問題描述

list= [ ..., 2648, 2648, 2648, 63370, 63370, 425, 425, 120, 120, 217, 217, 189, 189, 128, 128, 115, 115, 197, 19752, 152, 152, 275, 275, 1716, 1716, 131, 131, 98, 98, 138, 138, 277, 277, 849, 302, 152, 1571, 68, 68, 102, 102, 92, 92, 146, 146, 155, 155, 9181, 9181, 474, 449, 98, 98, 59, 59, 295, 101, ...]for i in list: if int(i/50)+1 not in dic:dic(int(i /50)+1)=list.count(i) else:dic(int(i /50)+1)+=list.count(i)

我這么寫總是報(bào)錯(cuò)，我想以 50bp 為一個(gè)區(qū)間進(jìn)行統(tǒng)計(jì)，即統(tǒng)計(jì)長度在 0-50 的頻數(shù)，50-100 的頻數(shù)...

我這么寫對(duì)么，應(yīng)該怎么寫呢?

問題解答

# code for python3from itertools import groupbylst= [ 2648, 2648, 2648, 63370, 63370, 425, 425, 120, 120, 217, 217, 189, 189, 128, 128, 115, 115, 197, 19752, 152, 152, 275, 275, 1716, 1716, 131, 131, 98, 98, 138, 138, 277, 277, 849, 302, 152, 1571, 68, 68, 102, 102, 92, 92, 146, 146, 155, 155, 9181, 9181, 474, 449, 98, 98, 59, 59, 295, 101, 5]for k, g in groupby(sorted(lst), key=lambda x: x//50): print(’{}-{}: {}’.format(k*50, (k+1)*50-1, len(list(g))))

結(jié)果:

0-49: 150-99: 10100-149: 15150-199: 8200-249: 2250-299: 5300-349: 1400-449: 3450-499: 1800-849: 11550-1599: 11700-1749: 22600-2649: 39150-9199: 219750-19799: 163350-63399: 2

不要使用內(nèi)建函數(shù)的名字: list 作為變數(shù)名

你想要的區(qū)間重疊了, 比如說元素 50 就不知道要分在 0-50 還是 50-100 了

存取字典應(yīng)該用 [] 而不是 ()

我回答過的問題: Python-QA

for i in list i是list中的內(nèi)容，應(yīng)該是for I in range(len(list))