問題描述

如下面這段代碼，我想把map和zip做出同樣的效果

name=[’a’,’b’,’c’]age=[10,11,12]nation=[’中國’,’にほん’,’Deutsch’]U1=list(zip(name,age,nation))print(U1)U2=map(None,name,age,nation)print(list(U2))

可是顯示：

[(’a’, 10, ’中國’), (’b’, 11, ’にほん’), (’c’, 12, ’Deutsch’)]Traceback (most recent call last): File 'F:/python/PT/program/nine neijian3.py', line 8, in <module> print(list(U2))TypeError: ’NoneType’ object is not callable

但是我去掉map里面的None：

U2=map(name,age,nation)print(list(U2))

顯示：

print(list(U2))TypeError: ’list’ object is not callable`

請各位大神賜教。

問題解答

map(lambda a,b,c: (a,b,c), name, age, nation)

name=[’a’,’b’,’c’]age=[10,11,12]nation=[’中國’,’にほん’,’Deutsch’]U1=list(zip(name,age,nation))print(U1)U2 = map(lambda a,b,c: (a,b,c), name, age, nation)print(list(U2))

第一個報錯NoneType ，是用于None object，所以不能輸出很正常。NoneType is the type for the None object, which is an object that indicates no value. You cannot add it to strings or other objects.

Python map()方法好像不是你這么用的，據(jù)我了解是應(yīng)該是這個樣子的。描述很簡單，第一個參數(shù)接收一個函數(shù)名，第二個參數(shù)接收一個可迭代對象。語法map(f, iterable)基本上等于：[f(x) for x in iterable]實例

>>> def add100(x):... return x+100... >>> hh = [11,22,33]>>> map(add100,hh)[111, 122, 133]

http://stackoverflow.com/ques...