問題描述

數組a

var a = [{key:1,name:’name1’},{key:2,name:’name2’},{key:3,name:’name3’},{key:4,name:’name4’},{key:5,name:’name5’}];

當數組b為 var b = [{key:1,name:’name1’}];，最后的結果應該是[{key:2,name:’name2’},{key:3,name:’name3’},{key:4,name:’name4’},{key:5,name:’name5’}]

當數組b為var b = [{key:3,name:’name3’},{key:4,name:’name4’}];，最后的結果應該是[{key:1,name:’name1’},{key:2,name:’name2’},{key:5,name:’name5’}]

也就是想得到數組a-數組b的結果。

使用difference只對數組有效，對里面是對象并沒有效

var a2 = [1,2,3,4,5];var b2 = [1,5];console.log(_.difference(a2,b2))

問題解答

_.differenceWith(a, b, _.isEqual)