問題描述

數組a

[{key:1,name:’name1’},{key:2,name:’name2’},{key:3,name:’name3’},{key:4,name:’name4’},{key:5,name:’name5’}]

數組b是在數組a的一部分

[{key:1,name:’name1’},{key:2,name:’name2’}]

數組c是在數組b的基礎上進行修改

[{key:1,name:’name11’},{key:22,name:’name22’}]

現在需要最后的結果為key:1被修改，key:2被刪除，key:3，key:4，key:5無變化保留，key:22被添加

[{key:1,name:’name11’},{key:3,name:’name3’},{key:4,name:’name4’},{key:5,name:’name5’},{key:22,name:’name22’}]

請問一下如何才能實現這個邏輯

問題解答

你是要比較還是合并？合并用 deepmerge 很方便

//引入Lodash_.extend(_.difference(a, b), c)回答3：

var a = [{key:1,name:’name1’},{key:2,name:’name2’},{key:3,name:’name3’},{key:4,name:’name4’},{key:5,name:’name5’}];var b = [{key:1,name:’name1’},{key:2,name:’name2’}];var c = [{key:1,name:’name11’},{key:22,name:’name22’}];var d = [];d = $.extend(a,(b,c));console.log(d);

extend方法 跟git 的merge差不多我那樣寫應該會得到你最后想要的那種結果

function compare(val1,val2){ if(val1 < val2){return 1; }else if(val1 > val2){return -1; }else{return 0; }}var values = [1,2,50,60,10,20,80];values.sort(compare);alert(values); //80,60,50,20,10,2,1回答5：

如果找不到好的工具，或者不想污染命名空間，那就把數組解耦，這樣應該可以滿足你的要求

let a = [{ key: 1, name: ’name1’ }, { key: 3, name: ’name3’ }, { key: 2, name: ’name2’ }, { key: 4, name: ’name4’ }, { key: 5, name: ’name5’ }];let b = [{ key: 1, name: ’name1’ }, { key: 2, name: ’name2’ }];let c = [{ key: 22, name: ’name22’ }, { key: 1, name: ’name11’ }];let akeys = a.map(x => x.key);let aname = a.map(x => x.name)let bkeys = b.map(x => x.key)//1,2let bname = b.map(x => x.name)let ckeys = c.map(x => x.key)//1,22let cname = c.map(x => x.name)ckeys.forEach(function (key, index) { if (bkeys.includes(key)) a[akeys.indexOf(key)].name = cname[ckeys.indexOf(key)] else { a[akeys.indexOf(bkeys[1])].key = key a[akeys.indexOf(bkeys[1])].name = cname[ckeys.indexOf(key)] }})console.log(a)回答6：

給你一段代碼拿去想象（只適用與數組合并），將下面的代碼拿到控制臺輸出一下就行了

function arrayExtends(){ var arrs = Array.prototype.slice.call(arguments); if(arrs.length < 2){return arrs[0]; } var save = arrs.pop(),now; while(now = arrs.pop()){for( var i = 0 , len = save.length; i < len; i++ ){ now[i] = save[i];}save = now; } return save;}arrayExtends([1,2,3,6,7],[4,5,{hello:'world'}],[{key:1,name:'zz'}]);

然后修改下適應你的需求：

function arrayExtends(){ var arrs = Array.prototype.slice.call(arguments); if(arrs.length < 2){return arrs[0]; } var save = arrs.pop(),now; while(now = arrs.pop()){for( var i = 0 , len = save.length; i < len; i++ ){ now[i] = save[i];}save = now; } var result = save.sort(function(a,b){return a.key - b.key; }); return result;}arrayExtends([{key:1,name:'zz'}],[{key:2,name:'zz'},{key:3,name:'zz'}]);