我們有三張表，我們需要分類統計一段時間內抗生素的不同藥敏結果，即 report_item_drugs 表的 drugs_result， 在不同項目project_name 和不同抗生素 antibiotic_dict_name 下的占比，并將藥敏結果顯示在行上，效果如下：

三張原始表（僅取需要的字段示例），分別是：

報告表

項目表

抗生素表（藥敏結果drugs_result為一列值）

1、按照項目、抗生素分組求出檢出的總數

SELECT A.project_name,A.antibiotic_dict_name,SUM(nums) AS 檢出總數FROM ( SELECT i.project_name,d.antibiotic_dict_name,d.drugs_result,COUNT(d.id) AS nums FROM `report` r RIGHT JOIN report_item i ON r.id=i.report_id RIGHT JOIN report_item_drugs d ON d.report_item_id=i.id WHERE r.report_status=2 AND r.add_date BETWEEN ’2020-01-01’ AND ’2020-12-30’GROUP BY i.project_id,d.antibiotic_dict_id,d.drugs_result ) A GROUP BY A.project_name,A.antibiotic_dict_name

2、按照項目、抗生素、藥敏結果求出不同藥敏結果數量

SELECT i.project_name,d.antibiotic_dict_name,IF(d.drugs_result<>’’, d.drugs_result, ’未填寫’) AS drugs_result,COUNT(d.id) AS 數量 FROM `report` rRIGHT JOIN report_item i ON r.id=i.report_idRIGHT JOIN report_item_drugs d ON d.report_item_id=i.idWHERE r.report_status=2 AND r.add_date BETWEEN ’2020-01-01’ AND ’2020-12-30’ GROUP BY i.project_id,d.antibiotic_dict_id,d.drugs_result

3、將兩個結果關聯到一起

SELECT BB.project_name,BB.antibiotic_dict_name,BB.drugs_result,BB.`數量`,AA.`檢出總數` FROM ( SELECT A.project_name,A.antibiotic_dict_name,SUM(nums) AS 檢出總數 FROM ( SELECT i.project_name,d.antibiotic_dict_name,d.drugs_result,COUNT(d.id) AS nums FROM `report` r RIGHT JOIN report_item i ON r.id=i.report_id RIGHT JOIN report_item_drugs d ON d.report_item_id=i.id WHERE r.report_status=2 AND r.add_date BETWEEN ’2020-01-01’ AND ’2020-12-30’ GROUP BY i.project_id,d.antibiotic_dict_id,d.drugs_result ) A GROUP BY A.project_name,A.antibiotic_dict_name) AA RIGHT JOIN ( SELECT i.project_name,d.antibiotic_dict_name,IF(d.drugs_result<>’’, d.drugs_result, ’未填寫’) AS drugs_result,COUNT(d.id) AS 數量 FROM `report` r RIGHT JOIN report_item i ON r.id=i.report_id RIGHT JOIN report_item_drugs d ON d.report_item_id=i.id WHERE r.report_status=2 AND r.add_date BETWEEN ’2020-01-01’ AND ’2020-12-30’ GROUP BY i.project_id,d.antibiotic_dict_id,d.drugs_result )BB ON AA.project_name=BB.project_name AND AA.antibiotic_dict_name=BB.antibiotic_dict_name WHERE AA.`檢出總數`<>’’

4、一般來說，到上一步不同藥敏數量和總數都有了，可以直接求比例了

但是，我們需要的是將藥敏顯示到行上，直接求比不符合需求，所以我們需要將列轉換為行

我們借助于case when實現行列轉換，并將藥敏結果根據字典轉為方便閱讀的漢字

SELECT C.project_name 項目名稱,C.antibiotic_dict_name 抗生素名稱,C.`檢出總數`, SUM(CASE C.`drugs_result` WHEN ’D’ THEN C.`數量` ELSE 0 END ) AS ’劑量依賴性敏感’, CONCAT(SUM(CASE C.`drugs_result` WHEN ’D’ THEN FORMAT(C.`數量`/C.`檢出總數`*100,2) ELSE 0 END),’%’) AS ’劑量依賴性敏感比率’, SUM(CASE C.`drugs_result` WHEN ’R’ THEN C.`數量` ELSE 0 END ) AS ’耐藥’, CONCAT(SUM(CASE C.`drugs_result` WHEN ’R’ THEN FORMAT(C.`數量`/C.`檢出總數`*100,2) ELSE 0 END),’%’) AS ’耐藥比率’, SUM(CASE C.`drugs_result` WHEN ’S’ THEN C.`數量` ELSE 0 END ) AS ’敏感’, CONCAT(SUM(CASE C.`drugs_result` WHEN ’S’ THEN FORMAT(C.`數量`/C.`檢出總數`*100,2) ELSE 0 END),’%’) AS ’敏感比率’, SUM(CASE C.`drugs_result` WHEN ’I’ THEN C.`數量` ELSE 0 END ) AS ’中介’, CONCAT(SUM(CASE C.`drugs_result` WHEN ’I’ THEN FORMAT(C.`數量`/C.`檢出總數`*100,2) ELSE 0 END),’%’) AS ’中介比率’, SUM(CASE C.`drugs_result` WHEN ’n1’ THEN C.`數量` ELSE 0 END ) AS ’非敏感’, CONCAT(SUM(CASE C.`drugs_result` WHEN ’n1’ THEN FORMAT(C.`數量`/C.`檢出總數`*100,2) ELSE 0 END),’%’) AS ’非敏感比率’, SUM(CASE C.`drugs_result` WHEN ’N’ THEN C.`數量` ELSE 0 END ) AS ’無’, CONCAT(SUM(CASE C.`drugs_result` WHEN ’N’ THEN FORMAT(C.`數量`/C.`檢出總數`*100,2) ELSE 0 END),’%’) AS ’無比率’, SUM(CASE C.`drugs_result` WHEN ’未填寫’ THEN C.`數量` ELSE 0 END ) AS ’未填寫’, CONCAT(SUM(CASE C.`drugs_result` WHEN ’未填寫’ THEN FORMAT(C.`數量`/C.`檢出總數`*100,2) ELSE 0 END),’%’) AS ’未填寫比率’FROM( SELECT BB.project_name,BB.antibiotic_dict_name,BB.drugs_result,BB.`數量`,AA.`檢出總數` FROM ( SELECT A.project_name,A.antibiotic_dict_name,SUM(nums) AS 檢出總數 FROM ( SELECT i.project_name,d.antibiotic_dict_name,d.drugs_result,COUNT(d.id) AS nums FROM `report` r RIGHT JOIN report_item i ON r.id=i.report_id RIGHT JOIN report_item_drugs d ON d.report_item_id=i.id WHERE r.report_status=2 AND r.add_date BETWEEN ’2020-01-01’ AND ’2020-12-30’ GROUP BY i.project_id,d.antibiotic_dict_id,d.drugs_result ) A GROUP BY A.project_name,A.antibiotic_dict_name) AA RIGHT JOIN ( SELECT i.project_name,d.antibiotic_dict_name,IF(d.drugs_result<>’’, d.drugs_result, ’未填寫’) AS drugs_result,COUNT(d.id) AS 數量 FROM `report` r RIGHT JOIN report_item i ON r.id=i.report_id RIGHT JOIN report_item_drugs d ON d.report_item_id=i.id WHERE r.report_status=2 AND r.add_date BETWEEN ’2020-01-01’ AND ’2020-12-30’ GROUP BY i.project_id,d.antibiotic_dict_id,d.drugs_result )BB ON AA.project_name=BB.project_name AND AA.antibiotic_dict_name=BB.antibiotic_dict_name WHERE AA.`檢出總數`<>’’) CGROUP BY C.project_name,C.antibiotic_dict_name;

5、查看結果，成功轉換

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